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Proof step 4 from proof int2int-inj (previous step)

i < 0 ⊦ bits2int(int2bits(i)) = i

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 5:
⊦ bits.first ∧ bits ≠ [] → bits2int(bits) = ~ bits2uint(bitsinvert(true + bits.rest) +1)
Proof step 6:
¬(int2bits(i).first ∧ int2bits(i) ≠ []), i < 0 ⊦ bits2int(int2bits(i)) = i
Proof step 10:
int2bits(i).first ∧ int2bits(i) ≠ [], i < 0 ⊦ ~ bits2uint(bitsinvert(true + int2bits(i).rest) +1) = i

Rule argument

name: bits2int-neg-01 rotate: F subst: [bits] → [int2bits(i)]

Additional information

Used terms: int2bits(i)