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Proof step 10 from proof int2int-rest-01 (previous step)

bits2uint(int2bits(j)) = bits2uint(true ' + false ' + bits), int2bits(j) = true ' + false ' + bits, j < 0, j < ~1 ⊦ j = 0, bits2uint(bits) = 2 ^ (1 + n→i(# bits)) + j

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 11:
⊦ j < 0 → bits2uint(int2bits(j)) = 2 ^ n→i(# int2bits(j)) + j
Proof step 12:
j < 0, 2 ^ n→i(# int2bits(j)) + j = bits2uint(true ' + false ' + bits), int2bits(j) = true ' + false ' + bits, j < 0, j < ~1 ⊦ j = 0, bits2uint(bits) = 2 ^ (1 + n→i(# bits)) + j

Rule argument

name: int2uint-neg rotate: F subst: [j] → [j]

Additional information

Used terms: j