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Proof step 14 from proof int2int-rest-01 (previous step)

#(false ' + bits) ≠ 0, j < 0, 2 ^ n→i(# int2bits(j)) + j = bits2uint(true ') * 2 ^ n→i(#(false ' + bits)) + bits2uint(false ' + bits), int2bits(j) = true ' + false ' + bits, j < 0, j < ~1 ⊦ j = 0, bits2uint(bits) = 2 ^ (1 + n→i(# bits)) + j

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 15:
int2bits(j) = true ' + false ' + bits, 2 ^ n→i(# int2bits(j)) + j = bits2uint(bits) + 2 ^ (1 + n→i(# bits)), j < 0, j < ~1 ⊦ j = 0, bits2uint(bits) = 2 ^ (1 + n→i(# bits)) + j

Rule argument

Additional information

Used simplifier rules: bits2uint-zeros-03: ⊦ bits2uint(false ' + bits) = bits2uint(bits);%bits2uint-one-03: ⊦ bits2uint(true ') = 1;% ⊦ m + 1 ≠ 0;% ⊦ i * j = j * i;% ⊦ i * j * j0 = (i * j) * j0;% ⊦ 1 * i = i;% ⊦ m + n = n + m;% ⊦ (m + n0) + n1 = m + n0 + n1;% ⊦ n→i(m + n) = n→i(m) + n→i(n);% ⊦ # boolvar ' = 0 +1;% ⊦ #(bits + bits0) = # bits + # bits0;% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;