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Proof step 18 from proof int2uint-neg (previous step)

0 < ~ j ∧ true ∈ uint2bits(~ j).rest.rest, j < 0 ⊦ bits2uint(bitsinvert(uint2bits(~ j)) +1) = 2 ^ n→i(# bitsinvert(uint2bits(~ j)) +1) + j

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 19:
true ∈ uint2bits(~ j).rest.rest, j < 0 ⊦ bits2uint(bitsinvert(uint2bits(~ j)) +1) = 2 ^ n→i(# bitsinvert(uint2bits(~ j)) +1) + j

Rule argument

Additional information

Used simplifier rules: ⊦ 0 < ~ i ↔ i < 0;