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Proof step 2 from proof int2uint-neg (previous step)

j < 0 ⊦ bits2uint(int2bits(j)) = 2 ^ n→i(# int2bits(j)) + j

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ i < 0 → int2bits(i) = sgn(bitsinvert(uint2bits(abs(i))) +1)
Proof step 4:
j < 0, j < 0 ⊦ bits2uint(sgn(bitsinvert(uint2bits(abs(j))) +1)) = 2 ^ n→i(# sgn(bitsinvert(uint2bits(abs(j))) +1)) + j

Rule argument

name: int2bits-neg rotate: F subst: [i] → [j]

Additional information

Used terms: j