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Proof step 6 from proof int2unit-inv-rest (previous step)

int2bits(i) = boolvar + bits ∧ int2bits(i) ≠ [], 0 < i ⊦ 2 ^ (n→i(# uint2bits(i)) - 1) = bits2uint(bitsinvert(bits)) + i + 1, bits ≠ [] ∧ bits.first

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
int2bits(i) = boolvar ' + bits, 0 < i, boolvar ∈ int2bits(i) ⊦ 2 ^ (n→i(# uint2bits(i)) - 1) = bits2uint(bitsinvert(bits)) + i + 1, bits ≠ [] ∧ bits.first

Rule argument

Additional information

Used simplifier rules: int2bits-not-empty: ⊦ int2bits(j) ≠ [];%bits2uint-base: ⊦ bits2uint([]) = 0;% ⊦ boolvar ' + bits = bits0 → boolvar ∈ bits0; (forward)% ⊦ bitsinvert([]) = [];% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ bits + [] = bits;% ⊦ boolvar + bits = boolvar ' + bits;