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Proof step 12 from proof ubits2bits (previous step)

¬(bits ≠ [] ∧ bits.last), bits.first, ∀ bits0. # bits0 < # bits → bits0.first → bits0 = [] ∨ 2 ^ n→i(# bits0) = bits2uint(bits0) + bits2uint(bitsinvert(bits0)) + 1 ⊦ 2 ^ n→i(# bits) = bits2uint(bits) + bits2uint(bitsinvert(bits)) + 1, bits = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 13:
bits.first, ∀ bits0. # bits0 < # bits → bits0.first → bits0 = [] ∨ 2 ^ n→i(# bits0) = bits2uint(bits0) + bits2uint(bitsinvert(bits0)) + 1 ⊦ 2 ^ n→i(# bits) = bits2uint(bits) + bits2uint(bitsinvert(bits)) + 1, bits = [], bits.last

Proof step 12 from proof ubits2bits (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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