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Proof step 2 from proof ubits2ubits-def (previous step)

true, ∀ bits0. # bits0 < # bits → true → uint2bits(bits2uint(bits0)) = sgn(false ' + bits0) ⊦ uint2bits(bits2uint(bits)) = sgn(false ' + bits)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information