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Proof step 31 from proof ubits2ubits-def (previous step)

false ↔ ¬ true, ∀ bits1. # bits1 < #(bits0 + true ') → true → uint2bits(bits2uint(bits1)) = sgn(false ' + bits1) ⊦ false ' + true ' = sgn(false ' + bits0) + true ', true ∈ bits0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 32:
∀ bits1. # bits1 < #(bits0 + true ') → true → uint2bits(bits2uint(bits1)) = sgn(false ' + bits1) ⊦ false ' = sgn(false ' + bits0), true ∈ bits0

Rule argument

Additional information

Used simplifier rules: ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ bits + bits0 = bits1 + bits0 ↔ bits = bits1;