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Proof step 6 from proof ubits2ubits-def (previous step)

∀ bits0. # bits0 < # bits → true → uint2bits(bits2uint(bits0)) = sgn(false ' + bits0) ⊦ ∀ bits0, boolvar. bits ≠ bits0 + boolvar ', uint2bits(bits2uint(bits)) = sgn(false ' + bits)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
∀ bits1. # bits1 < #(bits0 + boolvar ') → true → uint2bits(bits2uint(bits1)) = sgn(false ' + bits1) ⊦ uint2bits(bits2uint(bits0 + boolvar ')) = sgn(false ' + bits0 + boolvar ')

Proof step 6 from proof ubits2ubits-def (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information