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Proof step 3 from proof ubits2ubits-neg (previous step)

bits = boolvar + bits0, boolvar ⊦ bits = [], uint2bits(bits2uint(bits)) = false ' + bits

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
⊦ uint2bits(bits2uint(true ' + bits0)) = false ' + true ' + bits0

Rule argument

Additional information

Used simplifier rules: ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ boolvar ' + bits ≠ [];% ⊦ boolvar + bits = boolvar ' + bits;