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Proof step 4 from proof uint2bits-2pot-02 (previous step)

¬(0 < 2 ^ i - 1 ∧ 2 ^ i - 1 ≠ 1), 0 < i, ∀ i0. i→n(i0) < i→n(i) → 0 < i0 → uint2bits(2 ^ i0 - 1) = false ' + mklist(true, i→n(i0)) ⊦ uint2bits(2 ^ i - 1) = false ' + mklist(true, i→n(i))

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: uint2bits-one: ⊦ uint2bits(1) = false + true;% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ bits + bits0 = bits + bits1 ↔ bits0 = bits1;% ⊦ mklist(boolvar, 1) = boolvar ';% ⊦ boolvar + boolvar0 = boolvar ' + boolvar0 ';% ⊦ i < j ∧ j = i0 → i < i0; (forward)% ⊦ 2 ^ i = 2 ↔ i = 1;% ⊦ i - j = i0 ↔ i = i0 + j;% ⊦ i < j → (¬ ¬ j ≤ i ↔ false);% ⊦ i < 1 ↔ i ≤ 0;% ⊦ 2 ^ i ≤ 1 ↔ i < 1;% ⊦ ¬ i < j ↔ j ≤ i;% ⊦ i < j - i0 ↔ i + i0 < j;