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Proof step 5 from proof uint2bits-2pot-02 (previous step)

0 < 2 ^ i - 1 ∧ 2 ^ i - 1 ≠ 1, 0 < i, ∀ i0. i→n(i0) < i→n(i) → 0 < i0 → uint2bits(2 ^ i0 - 1) = false ' + mklist(true, i→n(i0)) ⊦ uint2bits((2 ^ i - 1) / 2) + ((2 ^ i - 1) % 2 = 1) = false ' + mklist(true, i→n(i))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
0 < i, 1 < 2 ^ i, 0 < 2 ^ i, 0 ≤ 2 ^ i, ∀ i0. i→n(i0) < i→n(i) → 0 < i0 → uint2bits(2 ^ i0 - 1) = false ' + mklist(true, i→n(i0)) ⊦ uint2bits((2 ^ i - 1) / 2) + ((2 ^ i - 1) % 2 = 1)' = false ' + mklist(true, i→n(i)), i = 1

Rule argument

Additional information

Used simplifier rules: ⊦ (* i) < j ∧ 0 < i → 0 ≤ j ∧ 0 < j; (forward)% ⊦ i < j - i0 ↔ i + i0 < j;% ⊦ 2 ^ i = 2 ↔ i = 1;% ⊦ i - j = i0 ↔ i = i0 + j;% ⊦ bits + boolvar = bits + boolvar ';