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Proof step 8 from proof uint2bits-2pot-04 (previous step)

uint2bits(i) = false ' + true ' + bits, false ∈ uint2bits(i), 0 ≤ i ⊦ bits2uint(uint2bits(i)) = bits2uint(false ' + true ' + bits), 2 ^ (n→i(# bits) + 1) = i + 1, false ∈ bits

User applied rule insert equation

And closed the goal!

Rule argument

pos: left 1 flags: discard

Additional information

Used simplifier rules: ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;