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Proof step 11 from proof uint2bits-2pot-05 (previous step)

2 ^ n→i(# bits) = i + 1, 0 ≤ i ⊦ uint2bits(i) = false ' + bits, false ∈ bits

User applied rule cut formula

And obtained the following new goals

Proof step 12:
i = 2 ^ n→i(# bits) - 1, 2 ^ n→i(# bits) = i + 1, 0 ≤ i ⊦ uint2bits(i) = false ' + bits, false ∈ bits

Rule argument

fma: i = 2 ^ n→i(# bits) - 1

Additional information

Used simplifier rules: ⊦ i - j = i0 ↔ i = i0 + j; Used formulas: i = 2 ^ n→i(# bits) - 1