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Proof step 2 from proof uint2bits-2pot-05 (previous step)

0 ≤ i ⊦ uint2bits(i) = boolvar ' + bits ↔ 2 ^ n→i(# bits) = i + 1 ∧ ¬ boolvar, false ∈ bits

User applied rule cut formula

And obtained the following new goals

Proof step 3:
0 ≤ i ⊦ boolvar, uint2bits(i) = boolvar ' + bits ↔ 2 ^ n→i(# bits) = i + 1 ∧ ¬ boolvar, false ∈ bits

Rule argument

fma: boolvar

Additional information

Used simplifier rules: uint2bits-first-01: ⊦ 0 ≤ i → uint2bits(i) ≠ true ' + bits;% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1; Used formulas: boolvar