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Proof step 10 from proof uint2bits-2pot-neg-mone (previous step)

0 < j, 0 < i, ∀ j, i0. i→n(i0) < i→n(i) → 0 < j ∧ 0 < i0 → uint2bits(j * 2 ^ i0 - 1) = uint2bits(j - 1) + mklist(true, i→n(i0)) ⊦ uint2bits((2 * 2 ^ (i - 1) * j - 1) / 2) + ((2 * 2 ^ (i - 1) * j - 1) % 2 ≠ 0)' = uint2bits(j - 1) + mklist(true, i→n(i)), 2 ^ (i - 1) * j = 1

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

seq: ⊦ i % 2 = 0 ∧ 0 < i → (i - 1) / 2 = i / 2 - 1 subst: [i] → [2 * 2 ^ (i - 1) * j] rotate: F spec: int-div inst: name: two-odd

Additional information

Used simplifier rules: ⊦ (i * 2) % 2 = 0;% ⊦ i * j * j0 = (i * j) * j0;% ⊦ i * j = j * i;% ⊦ 0 < i → (0 < i * j ↔ 0 < j);% ⊦ 0 < 2 ^ i ↔ 0 ≤ i;% ⊦ i ≤ j - i0 ↔ i + i0 ≤ j;% ⊦ 1 ≤ i ↔ 0 < i;% ⊦ ¬ i < j ↔ j ≤ i;% ⊦ i < j → (¬ ¬ j ≤ i ↔ false); Used terms: 2 * 2 ^ (i - 1) * j