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Proof step 4 from proof uint2bits-2pot (previous step)

0 < 2 ^ i ∧ 2 ^ i ≠ 1, 0 ≤ i, ∀ i0. i→n(i0) < i→n(i) → 0 ≤ i0 → uint2bits(2 ^ i0) = false ' + true ' + mklist(false, i→n(i0)) ⊦ uint2bits(2 ^ i / 2) + (2 ^ i % 2 = 1) = false ' + true ' + mklist(false, i→n(i))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
0 < 2 ^ i, 0 ≤ i, ∀ i0. i→n(i0) < i→n(i) → 0 ≤ i0 → uint2bits(2 ^ i0) = false ' + true ' + mklist(false, i→n(i0)) ⊦ 2 ^ i = 1, uint2bits(2 ^ i / 2) + (2 ^ i % 2 = 1)' = false ' + true ' + mklist(false, i→n(i))

Rule argument

Additional information

Used simplifier rules: ⊦ bits + boolvar = bits + boolvar ';