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Proof step 5 from proof uint2bits-2potrec (previous step)

0 ≤ i ∧ 2 ^ i < j, 0 ≤ i, 2 ^ i ≤ j ⊦ uint2bits(j) = uint2bits(j / 2 ^ i) + fillsgn(i→n(i) + 1, sgn(false ' + lastn(i→n(i), uint2bits(j).rest))).rest

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information