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Proof step 3 from proof uint2bits-add-high-01 (previous step)

j * 2 ^ i + j0 = (j - 1) * 2 ^ i + 2 ^ i + j0, 1 < j, 0 < j, j0 < 0, 0 < i, 2 ^ (i - 1) + j0 < 0, 0 ≤ j0 + 2 ^ i ⊦ uint2bits(j * 2 ^ i + j0) = uint2bits(j - 1) + fillsgn(i→n(i), int2bits(j0).rest)

User applied rule insert equation

And obtained the following new goals

Rule argument

pos: left 1 flags: discard

Additional information