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Proof step 17 from proof uint2bits-add-high-02 (previous step)

int2bits(j0) = true ' + bits, j0 < 0, 0 < i, 2 ^ (i - 1) + j0 < 0, 0 ≤ j0 + 2 ^ i ⊦ bits = [], j0 = 0, sgn(bits) = sgn(false ' + fillsgn(i→n(i), bits)), ¬ fillsgn(i→n(i), bits).first ∧ (i ≠ 0 ∨ bits ≠ [])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 18:
int2bits(j0) = true ' + bits, j0 < 0, 0 < i, 2 ^ (i - 1) + j0 < 0, 0 ≤ j0 + 2 ^ i, bits.first ⊦ bits = [], j0 = 0, sgn(bits) = sgn(false ' + fillsgn(i→n(i), bits))

Rule argument

Additional information

Used simplifier rules: ⊦ bits ≠ [] → (fillsgn(n, bits).first ↔ bits.first);