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Proof step 20 from proof uint2bits-add-high-02 (previous step)

fillsgn(i→n(i), int2bits(j0).rest) ≠ [] ∧ (fillsgn(i→n(i), int2bits(j0).rest).first ↔ false), 0 ≤ j0 + 2 ^ i, 2 ^ (i - 1) + j0 < 0, 0 < i, j0 < 0 ⊦ sgn(int2bits(j0).rest) = sgn(fillsgn(i→n(i), int2bits(j0).rest))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 21:
0 ≤ j0 + 2 ^ i, 2 ^ (i - 1) + j0 < 0, 0 < i, j0 < 0 ⊦ sgn(int2bits(j0).rest) = sgn(fillsgn(i→n(i), int2bits(j0).rest)), fillsgn(i→n(i), int2bits(j0).rest) = [], fillsgn(i→n(i), int2bits(j0).rest).first

Proof step 20 from proof uint2bits-add-high-02 (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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