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Proof step 23 from proof uint2bits-add-high-02 (previous step)

¬ int2bits(j0).rest ≠ [], 0 ≤ j0 + 2 ^ i, 2 ^ (i - 1) + j0 < 0, 0 < i, j0 < 0 ⊦ sgn(int2bits(j0).rest) = sgn(fillsgn(i→n(i), int2bits(j0).rest)), fillsgn(i→n(i), int2bits(j0).rest) = [], fillsgn(i→n(i), int2bits(j0).rest).first

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 24:
int2bits(j0).rest = [], j0 < 0, 0 < i, 2 ^ (i - 1) + j0 < 0, 0 ≤ j0 + 2 ^ i ⊦ i = 0, mklist(false, i→n(i)).first

Rule argument

Additional information

Used simplifier rules: ⊦ boolvar ' ≠ [];% ⊦ 0 < i → sgn(mklist(boolvar, i→n(i))) = boolvar ';% ⊦ fillsgn(n, []) = mklist(false, n);% ⊦ sgn([]) = [];% ⊦ i→n(i) = 0 ↔ i = 0;% ⊦ fillsgn(n, bits) = [] ↔ bits = [] ∧ n = 0;