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Proof step 1 from proof uint2bits-add-high (conclusion)

⊦ j < 0 ∧ 0 < i ∧ 2 ^ (i - 1) < abs(j) ∧ abs(j) ≤ 2 ^ i → uint2bits(j + 2 ^ i) = sgn(int2bits(j).rest)

User applied rule induction

And obtained the following new goals

Proof step 2:
true, ∀ i0, j. i→n(i0) < i→n(i) → true → j < 0 ∧ 0 < i0 ∧ 2 ^ (i0 - 1) < abs(j) ∧ abs(j) ≤ 2 ^ i0 → uint2bits(j + 2 ^ i0) = sgn(int2bits(j).rest) ⊦ j < 0 ∧ 0 < i ∧ 2 ^ (i - 1) < abs(j) ∧ abs(j) ≤ 2 ^ i → uint2bits(j + 2 ^ i) = sgn(int2bits(j).rest)

Rule argument

indvar: i→n(i) wfpred: <

Additional information

Used simplifier rules: <; (wellfounded) Used terms: i→n(i)