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Proof step 14 from proof uint2bits-add-low-01 (previous step)

0 < j, j0 < 0, 0 < i, 0 ≤ j0 + 2 ^ (i - 1), 2 ^ i + j0 < 0, 2 ^ i ≤ 2 ^ (i - 1) ⊦ j = 1, uint2bits(2 ^ i * j + j0) = uint2bits(j - 1) + fillsgn(i→n(i), int2bits(j0))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 15:
⊦ 0 ≤ i → (2 ^ i ≤ 2 ^ j ↔ i ≤ j)

Rule argument

seq: ⊦ 0 ≤ i → (2 ^ i ≤ 2 ^ j ↔ i ≤ j) subst: [j, i] → [i - 1, i] rotate: F spec: int-pot inst: name: two-le

Additional information

Used simplifier rules: ⊦ i < j → ¬ j < i;% ⊦ ¬ i ≤ j ↔ j < i;% ⊦ i ≤ j - i0 ↔ i + i0 ≤ j;% ⊦ i + j ≤ i ↔ j ≤ 0;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ i + j = j + i; Used terms: i - 1, i