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Proof step 3 from proof uint2bits-add-low-01 (previous step)

j = 1, 0 < j, j0 < 0, 0 < i, 0 ≤ j0 + 2 ^ (i - 1) ⊦ uint2bits(j * 2 ^ i + j0) = uint2bits(j - 1) + fillsgn(i→n(i), int2bits(j0))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
j0 < 0, 0 < i, 0 ≤ j0 + 2 ^ (i - 1) ⊦ uint2bits(2 ^ i + j0) = false ' + fillsgn(i→n(i), int2bits(j0))

Rule argument

Additional information

Used simplifier rules: uint2bits-zero: ⊦ uint2bits(0) = false ';% ⊦ i * j = j * i;% ⊦ i * j * j0 = (i * j) * j0;% ⊦ 1 * i = i;