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Proof step 33 from proof uint2bits-add-low (previous step)

0 < 2 ^ (i - 2), 0 < 2 ^ (i - 1), 1 < i, 0 ≤ 2 ^ (i - 1), 0 < 2 ^ i, 0 ≤ 2 ^ i, 1 < 2 ^ i, 0 < i, 0 ≤ i, ∀ i0, j. i→n(i0) < i→n(i) → true → j < 0 ∧ 0 < i0 ∧ abs(j) ≤ 2 ^ (i0 - 1) → uint2bits(j + 2 ^ i0) = false ' + fillsgn(i→n(i0), int2bits(j)) ⊦ i = 1, true ' + mklist(true, i→n(i) - 1) = mklist(true, i→n(i)), i→n(i) - 1 = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

seq: ⊦ n ≠ 0 → mklist(boolvar, n) = mklist(boolvar, n -1) + boolvar ' subst: [n, boolvar] → [i→n(i), true] rotate: F spec: list-last inst: bitlista name: mk-last-02

Additional information

Used simplifier rules: ⊦ i < j ∧ j = i0 → i < i0; (forward)% ⊦ i < j ∧ i = i0 → i0 < j; (forward)% ⊦ i→n(i) = 0 ↔ i = 0;% ⊦ n -1 = n - 1;% ⊦ mklist(boolvar, n) + boolvar ' = boolvar ' + mklist(boolvar, n);% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ bits + bits0 = bits + bits1 ↔ bits0 = bits1; Used terms: i→n(i), true