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Proof step 35 from proof uint2bits-add-low (previous step)

j < 0 ∧ j ≠ ~1, uint2bits(2 ^ (i - 1) + (j - 1) / 2) = false ' + fillsgn(i→n(i) - 1, int2bits((j - 1) / 2)), 0 < j + 2 ^ i, j < 2 ^ i, j + 1 < 2 ^ i, 1 < 2 ^ i, 0 < 2 ^ i, 0 ≤ 2 ^ i, 0 ≤ j + 2 ^ i, j ≤ 2 ^ (i - 1), j ≤ 2 ^ i, 0 ≤ 2 ^ (i - 1), 1 < j + 2 ^ i, j < 2 ^ (i - 1), j + 1 < i, 0 < 2 ^ (i - 1), 0 < i, 0 ≤ j + 2 ^ (i - 1), j < i, j + 1 < 2 ^ (i - 1), j < 0, abs(j - 1) / 2 ≤ 2 ^ (i - 2), ∀ i0, j. i→n(i0) < i→n(i) → true → j < 0 ∧ 0 < i0 ∧ abs(j) ≤ 2 ^ (i0 - 1) → uint2bits(j + 2 ^ i0) = false ' + fillsgn(i→n(i0), int2bits(j)) ⊦ i = 1, j = 0, fillsgn(i→n(i) - 1, int2bits((j - 1) / 2)) + (~1 = j % 2)' = fillsgn(i→n(i), int2bits((j - 1) / 2) + (~1 = j % 2)')

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 36:
uint2bits(2 ^ (i - 1) + (j - 1) / 2) = false ' + fillsgn(i→n(i) - 1, int2bits((j - 1) / 2)), abs(j - 1) / 2 ≤ 2 ^ (i - 2), j < 0, j + 1 < 2 ^ (i - 1), j < i, 0 ≤ j + 2 ^ (i - 1), 0 < i, 0 < 2 ^ (i - 1), j + 1 < i, j < 2 ^ (i - 1), 1 < j + 2 ^ i, 0 ≤ 2 ^ (i - 1), j ≤ 2 ^ i, j ≤ 2 ^ (i - 1), 0 ≤ j + 2 ^ i, 0 ≤ 2 ^ i, 0 < 2 ^ i, 1 < 2 ^ i, j + 1 < 2 ^ i, j < 2 ^ i, 0 < j + 2 ^ i, ∀ i0, j. i→n(i0) < i→n(i) → true → j < 0 ∧ 0 < i0 ∧ abs(j) ≤ 2 ^ (i0 - 1) → uint2bits(j + 2 ^ i0) = false ' + fillsgn(i→n(i0), int2bits(j)) ⊦ j = ~1, fillsgn(i→n(i) - 1, int2bits((j - 1) / 2)) + (~1 = j % 2)' = fillsgn(i→n(i), int2bits((j - 1) / 2) + (~1 = j % 2)'), j = 0, i = 1

Rule argument

Additional information

Used simplifier rules: ⊦ i + j = j + i;% ⊦ i + j + i0 = (i + j) + i0;