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Proof step 3 from proof uint2bits-div2pot-01 (previous step)

¬(0 ≤ i ∧ 2 ^ i ≤ j), 0 ≤ i, 0 < j, j % 2 ^ i = 0 ⊦ uint2bits(j) = uint2bits(j / 2 ^ i) + mklist(false, i→n(i))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
j % 2 ^ i = 0, 0 ≤ 2 ^ i, 0 < 2 ^ i, 0 ≤ i, j < 2 ^ i, 1 < 2 ^ i, 0 < j ⊦ uint2bits(j) = uint2bits(j / 2 ^ i) + mklist(false, i→n(i))

Rule argument

Additional information

Used simplifier rules: ⊦ 0 < j → i % j < j;% ⊦ (* i) < j ∧ 0 < i → 0 ≤ j ∧ 0 < j; (forward)% ⊦ i < j ∧ j < j0 → i < j0; (forward)% ⊦ i < j ∧ j < i0 → i +1 < i0; (forward)% ⊦ i < j ∧ i = i0 → i0 < j; (forward)% ⊦ i ≤ j → (¬ ¬ j < i ↔ false);% ⊦ ¬ i ≤ j ↔ j < i;