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Proof step 5 from proof uint2bits-expos1 (previous step)

uint2bits(j) = false ' + true ' + bits, false ∈ uint2bits(j), 0 ≤ j, 0 < j, 1 < j ⊦ ∃ bits. uint2bits(j) = false ' + true ' + bits ∧ bits ≠ []

User applied rule exists right

And obtained the following new goals

Proof step 6:
uint2bits(j) = false ' + true ' + bits, false ∈ uint2bits(j), 0 ≤ j, 0 < j, 1 < j ⊦ uint2bits(j) = false ' + true ' + bits ∧ bits ≠ [], ∃ bits. uint2bits(j) = false ' + true ' + bits ∧ bits ≠ []

Rule argument

pos: right 1 terms: bits abort: F discard: F computed: T

Additional information

Used terms: bits