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Proof step 2 from proof uint2bits-false (previous step)

uint2bits(i) = false ' + false ' + bits, 0 ≤ i ⊦

User applied rule insert lemma

And obtained the following new goals

Proof step 3:
⊦ 0 < i → uint2bits(i).rest.first
Proof step 4:
0 < i → uint2bits(i).rest.first, uint2bits(i) = false ' + false ' + bits, 0 ≤ i ⊦

Rule argument

name: uint2bits-second subst: [i] → [i]

Additional information

Used terms: i