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Proof step 19 from proof uint2bits-falsein-01 (previous step)

false ∈ uint2bits(i0).rest, false ∈ uint2bits(i0).rest ↔ (∀ i. 2 ^ i ≠ i0 + 1), 0 < i0, ∀ j0. i→n(j0) < i→n(i0 * 2 + 1) → 0 < j0 → (false ∈ uint2bits(j0).rest ↔ (∀ i. 2 ^ i ≠ j0 + 1)) ⊦ ∀ i. 2 ^ i ≠ 2 * (i0 + 1), i0 = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 20:
2 ^ i = 2 * (i0 + 1), false ∈ uint2bits(i0).rest, 0 < i0, ∀ i. 2 ^ i ≠ i0 + 1, ∀ j0. i→n(j0) < i→n(i0 * 2 + 1) → 0 < j0 → (false ∈ uint2bits(j0).rest ↔ (∀ i. 2 ^ i ≠ j0 + 1)) ⊦ i0 = 0

Proof step 19 from proof uint2bits-falsein-01 (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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