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Proof step 1 from proof uint2bits-falsein (conclusion)

⊦ 1 < i → false ∈ bitsinvert(uint2bits(i)) +1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
1 < i, 0 < i, 0 ≤ i ⊦ false ∈ bitsinvert(uint2bits(i)) +1

Rule argument

Additional information

Used simplifier rules: ⊦ (* i) < j ∧ 0 < i → 0 ≤ j ∧ 0 < j; (forward)