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Proof step 11 from proof uint2bits-falsein (previous step)

uint2bits(i) = bitsinvert(bits + false '), 0 ≤ i, 0 < i, 1 < i ⊦ false ∈ bits

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
uint2bits(i) = bitsinvert(bits) + true ', 1 < i, 0 < i, 0 ≤ i ⊦ false ∈ bits

Rule argument

Additional information

Used simplifier rules: uint2bits-onein: ⊦ 0 < j → true ∈ uint2bits(j);% ⊦ bits + boolvar ' = bits0 → boolvar ∈ bits0; (forward)% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ bitsinvert(false ') = true ';% ⊦ bitsinvert(bits + bits0) = bitsinvert(bits) + bitsinvert(bits0);