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Proof step 14 from proof uint2bits-falsein (previous step)

bits ≠ [], uint2bits(i) = ((¬ bits.first)' + bitsinvert(bits.rest)) + true ', 1 < i, 0 < i, 0 ≤ i ⊦ false ∈ bits

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 15:
uint2bits(i) = false ' + bitsinvert(bits.rest) + true ', 0 ≤ i, 0 < i, 1 < i, bits.first, false ∈ uint2bits(i) ⊦ bits = [], false ∈ bits

Rule argument

Additional information

Used simplifier rules: uint2bits-firstpos: ⊦ uint2bits(j) = boolvar ' + bits ∧ 0 ≤ j → ¬ boolvar;% ⊦ boolvar ' + bits = bits0 → boolvar ∈ bits0; (forward)% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;