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Proof step 16 from proof uint2bits-falsein (previous step)

bits = boolvar + bits0, uint2bits(i) = false ' + bitsinvert(bits0) + true ', 0 ≤ i, 0 < i, 1 < i, boolvar, false ∈ uint2bits(i) ⊦ bits = [], false ∈ bits

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 17:
uint2bits(i) = false ' + bitsinvert(bits0) + true ', 0 ≤ i, 0 < i, 1 < i, false ∈ uint2bits(i) ⊦ false ∈ bits0

Rule argument

Additional information

Used simplifier rules: ⊦ ¬ boolvar ∈ boolvar0 ' + bits ↔ ¬(boolvar ↔ boolvar0) ∧ ¬ boolvar ∈ bits;% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ boolvar ' + bits ≠ [];% ⊦ boolvar + bits = boolvar ' + bits;