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Proof step 19 from proof uint2bits-falsein (previous step)

¬ bits0 ≠ [], uint2bits(i) = false ' + bitsinvert(bits0) + true ', 0 ≤ i, 0 < i, 1 < i, false ∈ uint2bits(i) ⊦ false ∈ bits0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 20:
uint2bits(i) = false ' + true ', 0 ≤ i, 0 < i, 1 < i, false ∈ uint2bits(i) ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ ¬ boolvar ∈ [];% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ [] + bits = bits;% ⊦ bitsinvert([]) = [];