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Proof step 22 from proof uint2bits-falsein (previous step)

bits0 ≠ [], uint2bits(i) = false ' + ((¬ bits0.first)' + bitsinvert(bits0.rest)) + true ', 0 ≤ i, 0 < i, 1 < i, false ∈ uint2bits(i) ⊦ false ∈ bits0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 23:
uint2bits(i) = false ' + ((¬ bits0.first)' + bitsinvert(bits0.rest)) + true ', 0 ≤ i, 0 < i, 1 < i, false ∈ uint2bits(i), (¬ bits0.first) ∈ uint2bits(i) ⊦ bits0 = [], false ∈ bits0

Rule argument

Additional information

Used simplifier rules: ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ bits = bits0 + boolvar ' + bits1 → boolvar ∈ bits; (forward)