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Proof step 5 from proof uint2bits-falsein (previous step)

1 < i, 0 < i, 0 ≤ i ⊦ bitsinvert(uint2bits(i)).last, false ∈ bitsinvert(uint2bits(i)).butlast

User applied rule insert elim lemma

And obtained the following new goals

Rule argument

seq: bits ≠ [] ⊦ (boolvar ↔ bits.last) ∧ bits0 = bits.butlast ↔ bits = bits0 + boolvar ' subst: [bits, boolvar, bits0] → [bitsinvert(uint2bits(i)), boolvar, bits] rotate: T spec: list-last inst: bitlista name: last-elim

Additional information

Used simplifier rules: uint2bits-empty: 0 ≤ i ⊦ uint2bits(i) ≠ [];% ⊦ bitsinvert(bits) = [] ↔ bits = [];%bits ≠ [] ⊦ (boolvar ↔ bits.last) ∧ bits0 = bits.butlast ↔ bits = bits0 + boolvar '; (elim) Used terms: bitsinvert(uint2bits(i)), boolvar, bits