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Proof step 4 from proof uint2bits-first-01 (previous step)

0 ≤ i → ¬ uint2bits(i).first, uint2bits(i) = true ' + bits, 0 ≤ i, true ∈ uint2bits(i) ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
uint2bits(i) = true ' + bits, 0 ≤ i, true ∈ uint2bits(i) ⊦ uint2bits(i).first

Rule argument

Additional information

Used simplifier rules: ⊦ i ≤ j → (¬ ¬ j < i ↔ false);% ⊦ ¬ i ≤ j ↔ j < i;