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Proof step 3 from proof uint2bits-first-04 (previous step)

uint2bits(~ j) = boolvar + bits ∧ uint2bits(~ j) ≠ [], j < 0, boolvar ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
uint2bits(~ j) = true ' + bits, j < 0 ⊦

Rule argument

Additional information

Used simplifier rules: uint2bits-empty-01: ⊦ i < 0 → uint2bits(~ i) ≠ [];%uint2bits-onein-01: ⊦ j < 0 → true ∈ uint2bits(~ j);% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ boolvar ' + bits = bits0 → boolvar ∈ bits0; (forward)% ⊦ boolvar + bits = boolvar ' + bits;