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Proof step 14 from proof uint2bits-len-add (previous step)

i→n(i) + 1 < # uint2bits(j0), j0 < 2 ^ i, 0 < j, 0 ≤ j0, 0 ≤ i ⊦ # fillsgn(i→n(i) + 1, uint2bits(j0)) - 1 = i→n(i)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 15:
⊦ 0 ≤ i → int2bits(i) = uint2bits(i)
Proof step 16:
0 ≤ j0, i→n(i) + 1 < # int2bits(j0), j0 < 2 ^ i, 0 < j, 0 ≤ j0, 0 ≤ i ⊦ # fillsgn(i→n(i) + 1, int2bits(j0)) - 1 = i→n(i)

Rule argument

name: int2bits-pos rotate: T subst: [i] → [j0]

Additional information

Used terms: j0