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Proof step 2 from proof uint2bits-len-min (previous step)

0 ≤ i, 0 ≤ j, 2 ^ i ≤ j, # uint2bits(j) ≤ i→n(i) + 1 ⊦

User applied rule insert spec-lemma

And obtained the following new goals

Proof step 3:
⊦ 0 < j → (∃ i. 0 ≤ i ∧ 2 ^ i ≤ j ∧ j < 2 ^ (i + 1))
Proof step 4:
0 < j → (∃ i. 0 ≤ i ∧ 2 ^ i ≤ j ∧ j < 2 ^ (i + 1)), 0 ≤ i, 0 ≤ j, 2 ^ i ≤ j, # uint2bits(j) ≤ i→n(i) + 1 ⊦

Rule argument

seq: ⊦ 0 < j → (∃ i. 0 ≤ i ∧ 2 ^ i ≤ j ∧ j < 2 ^ (i + 1)) subst: [j] → [j] rotate: F spec: int-pot inst: name: exin2pot

Additional information

Used terms: j