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Proof step 2 from proof uint2bits-len-mon-01 (previous step)

0 ≤ j, # uint2bits(j) < # uint2bits(i), i ≤ j, 0 ≤ i ⊦

User applied rule insert lemma

And obtained the following new goals

Proof step 3:
⊦ 0 ≤ i ∧ i ≤ j → # uint2bits(i) ≤ # uint2bits(j)

Rule argument

name: uint2bits-len-mon subst: [i, j] → [i, j]

Additional information

Used simplifier rules: ⊦ ¬ i ≤ j ↔ j < i;% ⊦ i ≤ j → (¬ ¬ j < i ↔ false);% ⊦ m ≤ n ∧ n < n0 → m < n0; (forward)% ⊦ m < n ∧ n ≤ n0 → m < n0; (forward)% ⊦ ¬ n < n; Used terms: i, j