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Proof step 14 from proof uint2bits-len (previous step)

0 ≤ j, 2 ^ (i0 + 1) ≤ j, j < 2 ^ (2 + i0), 0 < j, 0 ≤ i0, 2 ^ (i0 + 1) < 2 ^ (2 + i0), 0 < 2 ^ (2 + i0), 1 < 2 ^ (2 + i0), 0 ≤ 2 ^ (2 + i0), ∀ j0, i. i→n(j0) < i→n(j) → 0 ≤ i ∧ 2 ^ i ≤ j0 ∧ j0 < 2 ^ (i + 1) → # uint2bits(j0) = i→n(i + 2) ⊦ ¬ 2 ^ (i0 + 1) ≤ j / 2, # uint2bits(j / 2) + 1 = i→n(3 + i0), j = 1, ~1 = i0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 15:
0 ≤ 2 ^ (2 + i0), 1 < 2 ^ (2 + i0), 0 < 2 ^ (2 + i0), 2 ^ (i0 + 1) < 2 ^ (2 + i0), 0 ≤ i0, 0 < j, j < 2 ^ (2 + i0), 2 ^ (i0 + 1) ≤ j, 0 ≤ j, 2 ^ (i0 + 1) ≤ j / 2, ∀ j0, i. i→n(j0) < i→n(j) → 0 ≤ i ∧ 2 ^ i ≤ j0 ∧ j0 < 2 ^ (i + 1) → # uint2bits(j0) = i→n(i + 2) ⊦ ~1 = i0, j = 1, # uint2bits(j / 2) + 1 = i→n(3 + i0)

Proof step 14 from proof uint2bits-len (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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