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Proof step 26 from proof uint2bits-mod2pot (previous step)

¬(j % 2 = 0 ∧ 2 ^ i0 ≠ 0), uint2bits((j / 2) % 2 ^ i0) = sgn(false ' + lastn(i→n(i0), uint2bits(j / 2).rest)), 0 ≤ i0, 0 < j, 2 ^ i0 * 2 < j, ∀ j0, i. i→n(j0) < i→n(j) → 0 ≤ i ∧ 2 ^ i < j0 → uint2bits(j0 % 2 ^ i) = sgn(false ' + lastn(i→n(i), uint2bits(j0).rest)) ⊦ ~1 = i0, j = 1, uint2bits(j % (2 ^ i0 * 2)) = sgn(false ' + lastn(i→n(i0), uint2bits(j / 2).rest) + (j % 2 = 1)')

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 27:
uint2bits((j / 2) % 2 ^ i0) = sgn(false ' + lastn(i→n(i0), uint2bits(j / 2).rest)), 0 ≤ i0, 0 < j, 2 ^ i0 * 2 < j, ∀ j0, i. i→n(j0) < i→n(j) → 0 ≤ i ∧ 2 ^ i < j0 → uint2bits(j0 % 2 ^ i) = sgn(false ' + lastn(i→n(i), uint2bits(j0).rest)) ⊦ ~1 = i0, j = 1, uint2bits(j % (2 ^ i0 * 2)) = sgn(false ' + lastn(i→n(i0), uint2bits(j / 2).rest) + (j % 2 = 1)'), j % 2 = 0

Rule argument

Additional information

Used simplifier rules: ⊦ 0 ≤ j → 2 ^ j ≠ 0;