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Proof step 2 from proof uint2bits-onein (previous step)

0 < j ⊦ true ∈ uint2bits(j)

User applied rule insert lemma

And obtained the following new goals

Proof step 3:
⊦ 0 < i → uint2bits(i).rest.first
Proof step 4:
0 < j → uint2bits(j).rest.first, 0 < j ⊦ true ∈ uint2bits(j)

Rule argument

name: uint2bits-second subst: [i] → [j]

Additional information

Used terms: j