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Proof step 5 from proof uint2bits-pred (previous step)

0 < j - 1 ∧ j - 1 ≠ 1, 0 < j, ∀ j0. i→n(j0) < i→n(j) → 0 < j0 → uint2bits(j0 - 1) = sgn(bitsinvert(bitsinvert(uint2bits(j0)) +1)) ⊦ uint2bits((j - 1) / 2) + ((j - 1) % 2 = 1) = sgn(bitsinvert(bitsinvert(uint2bits(j)) +1))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: ⊦ (* i) < j ∧ 0 < i → 0 ≤ j ∧ 0 < j; (forward)% ⊦ i < j - i0 ↔ i + i0 < j;% ⊦ i - j = i0 ↔ i = i0 + j;% ⊦ bits + boolvar = bits + boolvar ';