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Proof step 31 from proof uint2bits-restsgn (previous step)

uint2bits(2 * 2 ^ i - i0) = true ' + boolvar0 ' + bits0, i0 * 2 < 4 * 2 ^ i, 0 ≤ 2 ^ i, 2 ^ i < i0 * 2, i0 < 2 ^ i, 1 < 2 ^ i, 0 < 2 ^ i, 0 ≤ i0, 0 < i0, 1 < i, 1 < i0, 0 < i, 0 ≤ i, ∀ j0, i. i→n(j0) < i→n(i0 * 2 + 0) → 0 < i ∧ 0 ≤ j0 ∧ 2 ^ i < j0 ∧ j0 < 2 * 2 ^ i → sgn(uint2bits(2 ^ (i + 2) - j0).rest) = uint2bits(2 ^ (i + 2) - j0).rest ⊦ sgn(boolvar0 ' + ((4 * 2 ^ i - i0 * 2) % 2 = 1)') = (boolvar0 ' + bits0) + ((4 * 2 ^ i - i0 * 2) % 2 = 1)', 4 * 2 ^ i = 1 + i0 * 2, (¬ boolvar0) ∈ bits0

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

name: uint2bits-first-01 rotate: F subst: [bits, i] → [boolvar0 ' + bits0, 2 * 2 ^ i - i0]

Additional information

Used simplifier rules: ⊦ i ≤ j - i0 ↔ i + i0 ≤ j;% ⊦ i + 0 = i;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ i + j = j + i;% ⊦ ¬ i ≤ j ↔ j < i;% ⊦ i < j ∧ j < i0 → i +1 < i0; (forward)% ⊦ i < j ∧ j < j0 → i < j0; (forward)% ⊦ i +1 = i + 1;% ⊦ 0 ≤ j1 ∧ j1 < j → (i0 * j + j1 < j ↔ i0 ≤ 0);% ⊦ i * j * j0 = (i * j) * j0;% ⊦ i * j = j * i; Used terms: boolvar0 ' + bits0, 2 * 2 ^ i - i0