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Proof step 78 from proof uint2bits-restsgn (previous step)

(¬ uint2bits(2 * 2 ^ i - i0).rest.first) ∈ uint2bits(2 * 2 ^ i - i0).rest.rest, i0 * 2 < 4 * 2 ^ i, 0 ≤ 2 ^ i, 2 ^ i < i0 * 2, i0 < 2 ^ i, 1 < 2 ^ i, 0 < 2 ^ i, 0 ≤ i0, 0 < i0, 1 < i, 1 < i0, 0 < i, 0 ≤ i, ∀ j0, i. i→n(j0) < i→n(i0 * 2 + 0) → 0 < i ∧ 0 ≤ j0 ∧ 2 ^ i < j0 ∧ j0 < 2 * 2 ^ i → sgn(uint2bits(2 ^ (i + 2) - j0).rest) = uint2bits(2 ^ (i + 2) - j0).rest ⊦ uint2bits(2 * 2 ^ i - i0).rest = [], 4 * 2 ^ i = 1 + i0 * 2, sgn(uint2bits(2 * 2 ^ i - i0).rest) = uint2bits(2 * 2 ^ i - i0).rest, i = 1, ¬ 2 * 2 ^ (i - 1) ≤ i0 ∧ ¬ i0 ≤ 2 ^ (i - 1)

User applied rule case distinction

And obtained the following new goals

Rule argument

pos: right 5

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